A body starts from rest with uniform acceleration. If its velocity after n second is f_z then its displacement in the last two seconds is
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\(: v_0 + m_3 \to 0 \quad v / n\)
Now, distance travelled in n sec . ⇒ ⇒ \(S_x = -\frac{1}{2} m c\) and distance travelled in \((n - 2) \sec\) ⇒ ⇒ \(S_{-2} = -\frac{1}{2} \alpha (n - 2)^2\)
\ \ Distance travelled in last two seconds,
S_n = S_{n-2} \(-\frac{1}{2} \alpha r^{2} - \frac{1}{2} \alpha (n - 2)^{2}\)
\(-\frac{\alpha}{2} n^{2} - (n - 2)^{2}\) \(-\frac{\alpha}{2}[n+(n-2)][n-(n-2)]\)
= \(\alpha'(2n - 2)\) \(-\frac{v'}{n}(2n - 2)\) \(\frac{-2n(s)-1}{n}\)
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