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CGP EDU Academic Team
Published on: September 12, 2026
A stone tied to a string of length l is whirled in a vertical circle with the other end of the string at the center. At a certain instant of time, the stone is at its lowest position and has a speed u. The magnitude of the change in its velocity as it reaches a position where the string is horizontal is
Text Solution
Verified by ExpertsThe correct answer is:
D
\(\frac{1}{2}mu^{2} - \frac{1}{2}mv^{2} - mgl\)
⇒ ⇒ \(v = \sqrt{u^2 + 2gl}\)
\(\left| v - u \right| = \sqrt{v^2 + u^2} = \sqrt{u^2 + v^2 - 2gl} = \sqrt{2u^2 - 2gl}\)
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