CGP Edu

Physics Motion in a Straight Line Mix Single Correct MCQ

Published by: CGP EDU Academic Team

Published on: September 12, 2026

The \overline{V} - t graph of a moving object is given in figure. The maximum acceleration is

\(1 \mathrm{cm} / \mathrm{sec}^2\)

\(2 \mathrm{cm} / \mathrm{sec}^{2}\)

\(3 \text{ cm/sec}^2\)

\(6 \text{ cm/sec}^2\)

Text Solution

Verified by Experts

The correct answer is:

Maximum acceleration means maximum change in velocity in minimum time interval.

In time interval t = 30 to \(t = 40 \text{ sec}\)

\(a = \frac{\Delta v}{\Delta t} = \frac{80 - 20}{40 - 30} = \frac{60}{10} = 6 \, \mathrm{cm/sec^2}\)

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