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CGP EDU Academic Team
Published on: September 12, 2026
A particle moves along the sides AB, BC, CD of a square of side 25 m with a velocity of 15 ms^{-1}. Its average velocity is
Text Solution
Verified by ExpertsThe correct answer is:
D
Average velocity = \(\frac{\text{Total displacement}}{\text{Time taken}}\) \(= \frac{25}{75/15}\) =5 m/s
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