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CGP EDU Academic Team
Published on: September 12, 2026
A stone tied to a string of length \(\mathcal{L}\) is whirled in a vertical circle with the other end of the string at the center. At a certain instant of time, the stone is at its lowest position and has a speed u. The magnitude of the change in its velocity as it reaches a position where the string is horizontal is
Text Solution
Verified by ExpertsThe correct answer is:
D
\(\frac{1}{2}mu^{2} - \frac{1}{2}mv^{2} = mgl\)
⇒ ⇒ \(v = \sqrt{u^{2} - 2gl}\)
\(\left| \vec{v} - \vec{u} \right| = \sqrt{u^{2} + v^{2}} = \sqrt{u^{2} + u^{2} - 2 g L} = \sqrt{2 (u^{2} - g L)}\)
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