Home Physics Newton's Laws of Motion Second Law of Motion A man weighing 80 kg is standing in a trolle…
Physics Newton's Laws of Motion Second Law of Motion MCQ (Single Correct)

A man weighing 80 kg is standing in a trolley weighing 320 kg. The trolley is resting on frictionless horizontal rails. If the man starts walking on the trolley with a speed of 1 m / s, then after 4 sec his displacement relative to the ground will be

A
5 m
B
4.8 m
C
3.2 m
D
3.0 m

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Text Solution

Verified by Experts
The correct answer is:
C

If the man starts walking on the trolley in the forward direction then whole system will move in backward direction with same momentum.

Momentum of man in forward direction = Momentum of system (man + trolley) in backward direction

⇒ ⇒ ⇒ ⇒

So the velocity of man w.r.t. ground

Displacement of man w.r.t. ground

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