Published by:
CGP EDU Academic Team
Published on: September 12, 2026
A block of mass 5 kg is moving horizontally at a speed of 1.5 m/s. A perpendicular force of 5N acts on it for 4 sec. What will be the distance of the block from the point where the force started acting
Text Solution
Verified by ExpertsThe correct answer is:
A
\(S_{\text{Horizontal}} = ut = 1.5 \times 4 = 6\, \text{m}\)
\(S_{\text{Vertical}} = \frac{1}{2} a t^{2} = \frac{1}{2} \frac{F}{m} t^{2} = \frac{1}{2} \times 1 \times 16 = 8 \text{ m}\)
\(S_{\text{Net}} = \sqrt{6^2 + 8^2} = 10 \, \text{m}\)
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
If a bullet of mass 5 gm moving with velocity 100 m /sec, penetrates the wooden block up to 6 cm. T…
A force of 100 dynes acts on mass of 5 gm for 10 sec. The velocity produced is
An object will continue moving uniformly until
A diwali rocket is ejecting 0.05 kg of gases per second at a velocity of 400 m/sec. The acceleratin…
A body of mass 2 kg moving on a horizontal surface with an initial velocity of 4 m/sec comes to res…
A body of mass 2 kg is hung on a spring balance mounted vertically in a lift. If the lift descends …