If in a stationary lift, a man is standing with a bucket full of water, having a hole at its bottom. The rate of flow of water through this hole is R_0 . If the lift starts to move up and down with same acceleration and then that rates of flow of water are R_u and \(\mathrm{R}_{d}\) , then
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Rate of flow will be more when elevator will move in upward direction with some acceleration because the net downward pull will be more and vice-versa.
\(F_{\text{upward}}(R_u) = m(g - a) \\ F_{\text{downward}}(R_d) = m(g + a) \Rightarrow F_{\text{at rest}}(R_0) = mg\)
Thus, relation between \(R_u \cdot R_o\) and R_d is R_u > R_o > R_d
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