A Gardner waters the plants by a pipe of diameter 1mm. The water comes out at the rate or 10 cm 3 /sec. The reactionary force exerted on the hand of the Gardner is
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Rate of flow of water \(\frac{V}{t} = \frac{10\,cm^{3}}{sec} = 10 \times 10^{-6} \frac{m^{3}}{sec}\)
Density of water \[\rho = \frac{10^{3} \, \text{kg}}{\text{m}^{3}}\]
Cross-sectional area of pipe \(A = \pi (0.5 \times 10^{-3})^{2}\)
Force \(= m \frac{dv}{dt} = \frac{mv}{t} = \frac{V \rho v}{t} = \frac{\rho V}{t} \times \frac{V}{At} = \left(\frac{V}{t}\right)^2 \frac{\rho}{A}\)
\(\left( \boxed{\times} v = \frac{V}{At} \right)\)
By substituting the value in the above formula we get
\(F = 0.127\,N\)
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