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CGP EDU Academic Team
Published on: September 12, 2026
A spring of force constant 800 N/m has an extension of 5cm. The work done in extending it from 5cm to 15 cm is
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Verified by ExpertsThe correct answer is:
B
$W = \frac{1}{2} k (x_2^2 - x_1^2) = \frac{1}{2} \times 800 \times (15^2 - 5^2) \times 10^{-4} = 8 \mathrm{J}$
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