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CGP EDU Academic Team
Published on: September 12, 2026
When a spring is stretched by 2 cm, it stores 100 J of energy. If it is stretched further by 2 cm, the stored energy will be increased by
Text Solution
Verified by ExpertsThe correct answer is:
C
$100 = \frac{1}{2}kx^{2}$ (given)
$W = \frac{1}{2} k \left( x_2^2 - x_1^2 \right) = \frac{1}{2} k \left[ (2x)^2 - x^2 \right]$
$= 3 \times \left( \frac{1}{2} k x^{2} \right) = 3 \times 100 = 300 \, J$
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