A clock S is based on oscillation of a spring and a clock P is based on pendulum motion. Both clocks run at the same rate on earth. On a planet having the same density as earth but twice the radius
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$g = \frac{4}{3} \pi \rho G R$ . If density is same then g \propto R
According to problem $R_{p} = 2 R_{e}$ ∴ ∴ $g_{p} = 2 g_{e}$
For clock P (based on pendulum motion) $T = 2 \pi \sqrt{\frac{l}{g}}$
Time period decreases on planet so it will run faster because $g_{p} > g_{e}$
For clock S (based on oscillation of spring) $T = 2 \pi \sqrt{\frac{m}{k}}$
So it does not change.
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