The work done in increasing the size of a soap film from 10…

Physics Surface Tension Surface Energy Single Correct MCQ

Published on: September 12, 2026

The work done in increasing the size of a soap film from 10 cm× 6 cm to 10 cm × 11 cm is 3 ×10 -4 joule. The surface tension of the film is

$1.5 \times 10^{-2} \mathrm{N/m}$

$3.0 \times 10^{-2} \mathrm{N/m}$

$6.0 \times 10^{-2} \, \mathrm{N/m}$

$11.0 \times 10^{-2} \mathrm{N/m}$

Text Solution

Verified by Experts

The correct answer is:

$W = T \times \Delta A$ ∴ ∴ $\mathrm{T} = \frac{\mathrm{W}}{\Lambda \mathrm{A}}$

$T = \frac{3 \times 10^{-4}}{2 \times (110 - 60) \times 10^{-4}}$ (Soap film has two surfaces)

= $3 \times 10^{-2} \mathrm{N/m}$

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