In an industrial process 10 kg of water per hour is to be heated from 20°C to 80°C. To do this steam at 150°C is passed from a boiler into a copper coil immersed in water. The steam condenses in the coil and is returned to the boiler as water at 90°C. how many kg of steam is required per hour.
(Specific heat of steam = 1 calorie per gm°C, Latent heat of vaporization = 540 cal/gm)
Text Solution
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Suppose m kg steam required per hour
Heat released by steam in following three steps
Q 3 = mc W Δ Δ θ θ = m × × 1 × × (100 – 90) = 10 m cal
Hence total heat given by the steam Q = Q 1 +Q 2 + Q 3 = 600 mcal ... (i)
Heat taken by 10 kg water
Hence Q = Q ′ ′ ⇒ ⇒ 600 m = 600 × × 10 3
⇒ ⇒ m = 10 3 gm = 1kg.
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