In a vertical U-tube containing a liquid, the two arms are maintained at different temperatures $t_{1}$ and $t_{2}$ . The liquid columns in the two arms have heights $l_1$ and $l_2$ respectively. The coefficient of volume expansion of the liquid is equal to
$(a) \frac{l_1 - l_2}{l_2 t_1 - l_1 t_2} \quad (b) \frac{l_1 - l_2}{l_1 t_1 - l_2 t_2} \quad (c) \frac{l_1 + l_2}{l_2 t_1 + l_1 t_2} \quad (d) \frac{l_1 + l_2}{l_1 t_1 + l_2 t_2}$
Text Solution
Verified by ExpertsA
Suppose, height of liquid in each arm before rising the temperature is l.
With temperature rise height of liquid in each arm increases i.e. l 1 > l and l 2 > l
Also $I=\frac{l_1}{1+\gamma t_1}=\frac{l_2}{1+\gamma t_2}$
⇒ ⇒ $l_1 + \gamma l_1 t_2 = l_2 + \gamma l_2 t_1$ ⇒ ⇒ $\gamma = \frac{I_1 - I_2}{I_2 t_1 - I_1 t_2}$
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems