A one-liter glass flask contains some mercury. It is found that at different temperatures the volume of air inside the flak remains the same. What is the volume of mercury in this flask if coefficient of linear expansion of glass is 9 × × 10 –6 /°C while of volume expansion of mercury is 1.8 × × 10 –4 /°C
Text Solution
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It is given that the volume of air in the flask remains the same. This means that the expansion
in volume of the vessel is exactly equal to the volume expansion of mercury.
i.e., $\Delta V_{g} = \Delta V_{L}$ or $V_g \gamma_g \Delta \theta = V_L \gamma_L \Delta \theta$
∴ ∴ $V_{L} = \frac{V_{g} \gamma_{g}}{\gamma_{L}} = \frac{1000 \times (3 \times 9 \times 10^{-6})}{1.8 \times 10^{-4}} = 150 \text{cc}$
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