During illness an 80 kg man ran a fever of 102.2°F instead of normal body temperature of 98.6°F. Assuming that human body is mostly water, how much heat is required to raise his temperature by that amount
Text Solution
Verified by ExpertsThe correct answer is:
B
Since 102.2°F → → 39°C and 98.6°F → → 39°C
Hence Δ Δ Q = m. s. Δ Δ Q = 80 × 1000 × (39 – 37)
= 16 × 10 4 cal = 160 kcal.
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
A glass flask is filled up to a mark with 50 cc of mercury at 18ºC. If the flask and contents are h…
Solids expand on heating because
An iron tyre is to be fitted on to a wooden wheel 1m in diameter. The diameter of tyre is 6 mm smal…
A glass flask of volume one liter at 0°C is filled, level full of mercury at this temperature. The …
A steel scale measures the length of a copper wire as when both are at (the calibration temperatu…
Two metal strips that constitute a thermostat must necessarily differ in their