Published by:
CGP EDU Academic Team
Published on: September 12, 2026
Latent heat of ice is 80 cal/gm. A man melts 60 g of ice by chewing in 1 minute. His power is
Text Solution
Verified by ExpertsThe correct answer is:
B
$W = JQ = J(\mathrm{mL}) \Rightarrow P \times t = J(\mathrm{mL}) \Rightarrow P = J\left(\frac{\mathrm{m}}{t}\right) L$ ;
where $m_{\overline{t}} = \overline{m} + \frac{m_{t_0} - \overline{m}}{t_0} \overline{t}$ rate of melting of ice by chewing $= \frac{60 \ gm}{min} = \frac{1 \ gm}{sec}$ ⇒ ⇒ P = 4.2 × × 1 × × 80 = 336 W.
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