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CGP EDU Academic Team
Published on: September 12, 2026
The potential energy of a particle executing S.H.M. is 2.5 J, when its displacement is half of amplitude. The total energy of the particle be
Text Solution
Verified by ExpertsThe correct answer is:
B
$\frac{\text{Potential energy (U)}}{\text{Total energy (E)}} = \frac{\frac{1}{2} m \omega^2 y^2}{\frac{1}{2} m \omega^2 a^2} = \frac{y^2}{a^2} \\ \text{So } \frac{2.5}{E} = \frac{\left(\frac{a}{2}\right)^2}{a^2} \Rightarrow E = 10J$
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