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CGP EDU Academic Team
Published on: September 12, 2026
Two masses $m_1$ and $m_2$ are suspended together by a massless spring of constant k. When the masses are in equilibrium, $m_1$ is removed without disturbing the system. Then the angular frequency of oscillation of $m_2$ is
Text Solution
Verified by ExpertsThe correct answer is:
B
With mass $m_{2}$ alone, the angular frequency
$\omega = \sqrt{\frac{k}{m_2}}$
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