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CGP EDU Academic Team
Published on: September 12, 2026
Two bodies M and N of equal masses are suspended from two separate massless springs of force constants k 1 and k 2 respectively. If the two bodies oscillate vertically such that their maximum velocities are equal, the ratio of the amplitude M to that of N is
Text Solution
Verified by ExpertsThe correct answer is:
D
Maximum velocity $= a \omega = a \sqrt{\frac{k}{m}}$
Given that $a_{1}\sqrt{\frac{K_{1}}{m}}=a_{2}\sqrt{\frac{K_{2}}{m}}$ ⇒ ⇒ $\frac{a_1}{a_2} = \sqrt{\frac{K_2}{K_1}}$
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