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CGP EDU Academic Team
Published on: September 12, 2026
A mass m is suspended from the two coupled springs connected in series. The force constant for springs are $K_1$ and $\mathrm{K}_2$ . The time period of the suspended mass will be
Text Solution
Verified by ExpertsThe correct answer is:
C
In series $k_{eq} = \frac{k_1 k_2}{k_1 + k_2}$ so time period $T = 2\pi \sqrt{\frac{m(k_1 + k_2)}{k_1 k_2}}$
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