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CGP EDU Academic Team
Published on: September 12, 2026
Two waves
$y_{1} = A_{1} \sin(\omega t - \beta_{1})$ , $y_{2} = A_{2} \sin(\omega t - \beta_{2})$
Superimpose to form a resultant wave whose amplitude is
Text Solution
Verified by ExpertsThe correct answer is:
A
Phase difference between the two waves is
$\varphi = (\omega t - \beta_2) = (\omega t - \beta_1) = (\beta_1 - \beta_2)$
∴ ∴ Resultant amplitude $A = \sqrt{A_1^2 + A_2^2 + 2 A_1 A_2 \cos(\beta_1 - \beta_2)}$
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