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CGP EDU Academic Team
Published on: September 12, 2026
The displacement of the interfering light waves are $y_{1} = 4 \sin \omega t$ and $y_{2} = 3 \sin \left( \omega t + \frac{\pi}{2} \right)$ . What is the amplitude of the resultant wave
Text Solution
Verified by ExpertsThe correct answer is:
A
Since $\varphi = \frac{\pi}{2}$ ⇒ ⇒ $A = \sqrt{a_1^2 + a_2^2} = \sqrt{(4)^2 + (3)^2} = 5$
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