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CGP EDU Academic Team
Published on: September 11, 2026
The acceleration of a particle performing S.H.M. is $12\ \mathrm{cm/sec^{2}}$ at a distance of $3 \text{ cm}$ from the mean position. Its time period is
Text Solution
Verified by ExpertsThe correct answer is:
D
$T = 2 \pi \sqrt{\frac{\text{Displacement}}{\text{Acceleration}}} = 2 \pi \sqrt{\frac{3}{12}} = \pi = 3.14 \text{ sec}$
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