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CGP EDU Academic Team
Published on: September 12, 2026
A charge q is placed at the center of the open end of cylindrical vessel. The flux of the electric field through the surface of the vessel is
Text Solution
Verified by ExpertsThe correct answer is:
C
$Total flux through the cylindrical gaussian surface = \frac{q}{\epsilon_0} Flux through open cylinder = \frac{1}{2} (\text{Total flux}) = \frac{q}{2 \epsilon_0}$
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