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CGP EDU Academic Team
Published on: September 12, 2026
Two capacitors of capacities $C_1$ and $C_2$ are charged to voltages $V_{1}$ and $V_2$ respectively. There will be no exchange of energy in connecting them in parallel, if
Text Solution
Verified by ExpertsThe correct answer is:
C
$Loss of energy = \frac{1}{2} \left(\frac{C_1 C_2}{C_1 + C_2}\right) (V_1 - V_2)^2 If V_1 = V_2, loss of energy = 0$
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