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CGP EDU Academic Team
Published on: September 12, 2026
The capacities of two conductors are $C_1$ and $C_2$ and their respective potentials are $\vec{V}_{1}$ and $V_{2}$ . If they are connected by a thin wire, then the loss of energy will be given by
Text Solution
Verified by ExpertsThe correct answer is:
C
Initial energy $U_i = \frac{1}{2} c_1 V_1^2 + \frac{1}{2} c_2 V_2^2$ ,
Final energy $U_{f} = \frac{1}{2} (c_{1} + c_{2}) v^{2}$ (where $V = \frac{C_1 V_1 + C_2 V_2}{C_1 C_2}$
Hence energy loss $\Delta U = U_i - U_f = \frac{C_1 C_2}{2(C_1 + C_2)} (V_1 - V_2)^2$
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