A machine gun fires a bullet of mass 40 g with a velocity 1200 ms -1 . The man holding it can exert a maximum force of 144 N on the gun. How many bullets can he fire per second at the most
Text Solution
Verified by ExpertsD
\(\mathbf{u} =\) velocity of bullet
\(\frac{dm}{dt} = \text{Mass fired per second by the gun} \\
\frac{dm}{dt} = \text{Mass of bullet (m}_{B}\text{) } \times \text{ Bullets fired per sec (N)}\)
Maximum force that man can exert \(\mathbf{F} = u \left( \frac{dm}{dt} \right)\)
\(\therefore F = u \times m_{B} \times N \\ \Rightarrow N = \frac{F}{m_{B} \times u} = \frac{144}{40 \times 10^{-3} \times 1200} = 3\)
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems