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CGP EDU Academic Team
Published on: September 12, 2026
0.2 F capacitor is charged to $600 \sqrt{v}$ by a battery. On removing the battery, it is connected with another parallel plate condenser of 1F. The potential decreases to
Text Solution
Verified by ExpertsThe correct answer is:
A
By using charge conservation $0.2 \times 600 = (0.2 + 1)V$
⇒ ⇒ $v = \frac{0.2 \times 600}{1.2} = 100 \, V$
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