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CGP EDU Academic Team
Published on: September 12, 2026
A potential difference of 300 volts is applied to a combination of 2.0 μ μ F and 8.0 μ μ F capacitors connected in series. The charge on the 2.0 μ μ F capacitor is
Text Solution
Verified by ExpertsThe correct answer is:
B
In series combination charge Q is same. So charge on 2 μ μ F capacitor is
$Q = C_{eq} V = \left(\frac{2 \times 8}{2 + 8}\right) \times 300 \times 10^{-6}$ $= 4.8 \times 10^{-4} C$
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