Published by:
CGP EDU Academic Team
Published on: September 12, 2026
In a hollow spherical shell potential (V) changes with respect to distance (r) from center
A
B
C
D
Text Solution
Verified by ExpertsThe correct answer is:
B
$V_{inside} = \frac{Q}{4 \pi \varepsilon_0 R}$ for $r \leq R$ ....(i)
and $V_{out} = \frac{Q}{4 \pi \epsilon_0 r}$ for $r \geq R$ ....(ii)
i.e. potential inside the hollow spherical shell is constant and outside varies according to $V \propto \frac{1}{r}$ .
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