When a resistor of 11 Ω Ω is connected in series with an electric cell, the current flowing in it is 0.5 A. Instead, when a resistor of 5 Ω Ω is connected to the same electric cell in series, the current increases by 0.4 A. The internal resistance of the cell is
Text Solution
Verified by ExpertsThe correct answer is:
C
By using 
⇒ ⇒ 
..…(i)
and 
⇒ ⇒ 
..…(ii)
On solving these equation, we have 
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
In the adjoining circuit, the battery E 1 has an e.m.f of 12 volt and zero internal resistance whil…
The magnitude and direction of the current in the circuit shown will be
A cell of having a finite internal resistance is connected to a load resistance of . For maximum…
By a cell a current of 0.9 A flows through 2 ohm resistor and 0.3 A through 7 ohm resistor. The int…
The e.m.f. of a cell is E volts and internal resistance is ohm. The resistance in external circuit …
A cell of e.m.f. E is connected with an external resistance R, then p.d, across cell is V. The inte…