A boy can throw a stone to maximum height of 50 m. To what maximum range can he throw this stone and to what height so that the maximum range is maintained?
Text Solution
Verified by ExpertsThe correct answer is:
B
For maximum height, the boy has to throw the stone at θ θ = 90 o , then
H = u 2 /2g or u 2 = 2gH
or u 2 = 2 × 9.8 × 50 = 980 (ms -1 ) 2
maximum range R = u 2 /g = 980/9.8 = 100 m
Greatest height for maximum range is given by
H = 
= 
= 25 M
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