A ball is thrown from the ground to clear a wall 3 m high at a distance of 6 m and falls 18 m away from the wall, the angle of projection of ball is
Text Solution
Verified by ExpertsThe correct answer is:
B
Using R = u 2 sin 2 θ θ /g we get

g/u 2 = sin 2 θ θ /R
Range, R = 6 + 18 = 24 m
g/u 2 = sin 2 θ θ /24
As y = x tan θ θ - (gx 2 /2u 2 cos 2 θ θ )
for x = 6m, y = 3 m
and g/u 2 = sin 2 θ θ /24 we get
3 = 6 tan θ θ - 
Using sin 2 θ θ = 2 sin θ θ cos θ θ , we get
tan θ θ = 2/3 or θ θ = tan -1 (2/3)
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