A balloonist is ascending at a velocity of 12 ms -1 and acceleration 2 ms -2 . A packet is dropped from it when it is at a height of 65 m from the ground, it drops a packet. Time taken by the packet to reach the ground is
Text Solution
Verified by ExpertsThe correct answer is:
A
Using h = ut + 1/2 gt 2 we get
- 65 = 12t – 1/2 × 10 × t 2
or 5t 2 – 12t – 65 = 0
Solving t = 5 s or -13/5 s
Time cannot be negative, thus t = 5 s.
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
A particle moving in a straight line covers half the distance with speed of 3 m/s . The other half …
A particle starts from rest. Its acceleration ( a ) versus time ( t ) is as shown in the figure. Th…
A car accelerates from rest at a constant rate for some time, after which it decelerates at a cons…
A stone dropped from a building of height and it reaches after seconds on earth. From the same bu…
A ball is projected upwards from a height above the surface of the earth with velocity . The time…
A particle is dropped vertically from rest from a height. The time taken by it to fall through succ…