Engine of a vehicle can give it an acceleration of 1 ms -2 and its brakes can retard it at 3 ms -2 . The minimum time in which the vehicle can make a journey between stations A and B having a distance of 1200 m is
Text Solution
Verified by ExpertsThe correct answer is:
D
During acceleration v/t 1 = 1 t 1 = v
During retardation, v/t 2 = 3 or t 2 = v/3
Using s = 1/2 v(t 1 + t 2 ) [Displacement = area of Δ Δ ]
or 1200 = 1/2 v(v + v/3)
or 1200 = 2v 3 /3
or v 2 = 3600/2 = 1800
or v = 42.4
∴ ∴ t 1 + t 2 = 42.4 + 42. 4/3 = 56.5 s
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