A marble starts falling from rest on a smooth inclined plane of inclination α α . After covering distance h the ball rebounds off the plane. The distance from the impact point where the ball rebounds for the second time is
Text Solution
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Velocity before strike u = √ √ 2gh
Component of acceleration along the inclined plane = g sin α α and the perpendicular component = g cos α α
Using S = ut + 1/2 at 2
For vertical direction we get,
0 = v cos α α t – 1/2 g cos α α t 2 and
For horizontal direction
x = u sin α α t + 1/2 g sin α α t 2
= u sin α α 
= 
= 4 × 
= 8h sin α α
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