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Physics Motion in a Plane Mix MCQ (Single Correct)

A body is projected with velocity v at an angle of projection θ . Then match the following-

Column I

Column II

(i) Change in momentum

[A] Remains unchanged

(ii) Angle at the highest

point

[B] Independent of

projected velocity

(iii) Kinetic energy of body

[C] At highest point is

zero

(iv) Horizontal

Component of velocity

[D] Minimum at highest

point

A
(i) → [ B ] , (ii) → [ C ] , (iii) → [D], (iv) → [ A ]
B
(i) → [ A ] , (ii) → [ C ] , (iii) → [Β] , (iv) → [D]
C
(i) → [B], (ii) → [ D ] , (iii) → [ A ] , (iv) → [C]
D
(i) → [ D ] , (ii) → [ B ] , (iii) → [C], (iv) → [A]

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Text Solution

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The correct answer is:
CHECK THE SOLUTION.

Ans.

(i) [B]

(ii) [C]

(iii) [D]

(iv) [A]

Sol. Change in momentum is mgt in time t.

Angle at highest point is 0°.

Kinetic energy of body is minimum at highest point.

Horizontal component remains unchanged.

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