What is the maximum angle to the horizontal at which a stone can be thrown and always be moving away from the thrower?
Text Solution
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Sol. Using the coordinate system shown in the figure, the motion of the stone can be described by the following relations:
x = v 0 tcos α , y = v 0 t sin α –
t 2 ,
v x = v 0 cos α , v y = v 0 sin α – gt

The stone is at the greatest distance from the origin when its velocity is perpendicular to its position vector. The condition for this is
=
,
Which yields a quadratic equation for the time t at which this happens;
t 2 –
t +
= 0.
If this is not to happen, the discriminant of this equation must be negative i.e.,
< 4
.
Thus, for the stone to the permanently moving away from the thrower, we must have
sin α <
= 0.94. i.e. α < 70.5º.
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