A disc of radius 0.1 m rolls without sliding on a horizontal surface with a velocity of 6 m/s. It then ascends a smooth continuous track as shown in figure. The height upto which it will ascend is: (g = 10 m/s 2 )
Text Solution
Verified by ExpertsThe correct answer is:
D
Let m be the mass of the disc. Then translational kinetic energy of the disc is :
K T = 
mv 2 ... (1)
When it ascends on a smooth track its rotational kinetic energy will remain same while translational kinetic energy will go on decreasing. At highest point.
KT = mgh
or 
mv 2 = mgh
or h = 
= 
= 1.8 m
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