Published by:
CGP EDU Academic Team
Published on: September 12, 2026
A body of mass 1 kg thrown upwards with a velocity of 10 m/s comes to rest (momentarily) after moving up 4m. The work done by air drag in this process is (Take g = 10 m/s 2 )
Text Solution
Verified by ExpertsThe correct answer is:
B
According to work energy theorem
W gravitational force + W air drag = change in KE.
⇒ ⇒ 
+ W air drag = change in KE.
⇒ ⇒ − − mgh + W air drag = change in KE
⇒ ⇒ W air drag = change in KE + mgh = [0 − − 
mu 2 ] + mgh = − − 50 + 40 = − − 10 Joules.
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
A particle moves under the effect of a force F = Cx from $x=0$ to $x = x_1$ . The work done in the …
A cord is used to lower vertically a block of mass M by a distance d with constant downward acceler…
Two springs have their force constant as k 1 and $k_{2}(k_{1} > k_{2})$ . When they are stretched b…
The potential energy of a certain spring when stretched through a distance ‘S’ is 10 joule. The amo…
A position dependent force newton acts on a small body of mass 2 kg and displaces it from to . T…
A body of mass 3 kg is under a force, which causes a displacement in it is given by $S = t^{4} - 3t…