A body of mass 1 kg thrown upwards with a velocity of 10 m/s comes to rest (momentarily) after moving up 4m. The work done by air drag in this process is (Take g = 10 m/s 2 )
Text Solution
Verified by ExpertsThe correct answer is:
B
According to work energy theorem
W gravitational force + W air drag = change in KE.
⇒ ⇒ 
+ W air drag = change in KE.
⇒ ⇒ − − mgh + W air drag = change in KE
⇒ ⇒ W air drag = change in KE + mgh = [0 − − 
mu 2 ] + mgh = − − 50 + 40 = − − 10 Joules.
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