The switch S has been closed for long time and the electric circuit shown carries a steady current. Let C 1 = 3.0 µF, C 2 = 6.0 µF, R 1 = 4.0 kΩ, and R 2 = 7.0 kΩ. The power dissipated in R 2 is 2.8 W.
(i)The power dissipated to the resistor R 1 is-
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Ans.
(i)
Sol. i = 2 × 10 –2 A
i 2 R 1 = (2.0 × 10 –2 ) 2 × 4 × 10 3 = 1.6 W
(ii)
Sol. 
× C 1 = 80 × 3 × 10 –6 = 240 µC
× C 2 = 140 × 6 × 10 –6 = 840 µC
(iii)
Sol. 
= EC 1 = 220 × 3 × 10 –6 = 660 µC
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