Published by:
CGP EDU Academic Team
Published on: September 12, 2026
The distance between the plates of a plane capacitor is d and the area of each plate is A. As shown in the figure, both plates of the capacitor are earthed and a small body carrying charge Q is placed between them, at a distance x from one plate. What charge will accumulate on each plate?
Text Solution
Verified by ExpertsThe correct answer is:
A
Step 1: In a plane capacitor, when a charge Q is placed between the plates, it induces equal and opposite charges on the plates due to electrostatic induction.
Step 2: Let the distance of plate A from the charge Q be x and the distance of plate B be (d - x). The electric field E between the plates is given by the equation \( E = \frac{V}{d} \), where V is the potential difference.
Step 3: The induced charge on the plates can be calculated using the formula for capacitance given by \( C = \frac{Q}{V} \). The charge on each plate will actually be equal to the charge Q placed in the capacitor.
Therefore, the charge that accumulates on each plate is Q. Hence Option A is the correct answer.
Step 2: Let the distance of plate A from the charge Q be x and the distance of plate B be (d - x). The electric field E between the plates is given by the equation \( E = \frac{V}{d} \), where V is the potential difference.
Step 3: The induced charge on the plates can be calculated using the formula for capacitance given by \( C = \frac{Q}{V} \). The charge on each plate will actually be equal to the charge Q placed in the capacitor.
Therefore, the charge that accumulates on each plate is Q. Hence Option A is the correct answer.
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