The reading of a spring balance when a block is suspended from it in air is 60 newtons. This reading is changed to 40 newtons when the block is submerged in water. The specific gravity of the block must be therefore:
Text Solution
Verified by ExpertsThe correct answer is:
A
ρ V g = 60.................(i)
( ρ – σ )V g = 40 .................(ii)
but specific gravity = 
dividing (i) & (ii) 
= 3.
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