Physics Simple Harmonic Motion (Oscillations) Superposition of S.H.M’s and Resonance MCQ (Single Correct)

The amplitude of a particle due to superposition of following S.H.Ms. Along the same line is

X 1 = 2 sin 50 π t ; X 2 = 10 sin (50 π t + 37º)

X 3 = - 4 sin 50 π t ; X 4 = - 12 cos 50 π t

A
4
B
4
C
6
D
none of these

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Text Solution

Verified by Experts
The correct answer is:
C

Amplitude phasor diagram:

= =

∴ resultant amplitude = .

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