Published by:
CGP EDU Academic Team
Published on: September 12, 2026
Two balls are dropped from different heights. One ball is dropped 2 sec after the other but they both strike the ground at the same time, 3 sec after the first is dropped. The difference in the heights at which they were dropped is
Text Solution
Verified by ExpertsThe correct answer is:
D
h1 = 
g 2
h 2 = 
g (3 – 2) 2
h 1 – h 2 = 
g (9 – 1) = 4 × 9.8 = 39.2 m
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
A particle moving in a straight line covers half the distance with speed of 3 m/s . The other half …
A particle starts from rest. Its acceleration ( a ) versus time ( t ) is as shown in the figure. Th…
A car accelerates from rest at a constant rate \ddot{q} for some time, after which it decelerates a…
A stone dropped from a building of height h and it reaches after t seconds on earth. From the same …
A ball is projected upwards from a height \hat{h} above the surface of the earth with velocity \vec…
A particle is dropped vertically from rest from a height. The time taken by it to fall through succ…