A particle is projected from ground in vertical direction at t = 0. At t = 0.8 sec, it reaches h = 14m. It will again come to same height at t =------ [ g = 10 m/s 2 ]
sec.
sec.
Text Solution
Verified by ExpertsD
Taking upward direction as positive
initial velocity can be obtained by II equ. of motion i.e. s = ut + 1/2 at 2
considering motion from C to A
14 = u × 0.8 – 
× 10 × 0.8 2
so, u = 
m/s
(ii) Let velocity magnitude at point A = v
so, v = u – gt
v = 
– 10 × 0.8 = 
m/s
(iii) Hence time taken from A to B i.e. till same level = 
= 2.7 s
Hence the time instant at which the particle comes to same level
= 0.8 + 2.7 = 3.5 s
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