A particle of mass 500 gm is moving in a straight line with velocity u = bx 5/2 . The work done by the net force during its displacement from x = 0 to x = 4 mis: (Take b = 0.25 m -3/2 s -1 ).
Text Solution
Verified by ExpertsThe correct answer is:
D
By work energy theorem work done by net force = 
K.E.
w=16J
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