A block of mass 1 kg is stationary with respect to a conveyer belt that is accelerating with 1 m/s 2 upwards at an angle of 30º as shown in figure. Which of the following is/are correct?
A
Force of friction on block is 6 N upwards along the inclined plane.
B
Force of friction on block is 1.5 N upwards along the inclined plane.
C
Contact force between the block & belt is 10.5 N.
D
Contact force between the block & belt is 
N.
N.
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
(a, c) Block is moving upwards due to friction
f r – mg sin 30 = ma
f r – 1 × 10 × 
= 1 × 1
f r = 6 N
Contact force is the resultant of N and f r
= 
= 
= 10.5 N
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